Question

Two no.s are in ratio 4:5 if difference of their cube is 61 find the no.s

Answer 1

Let the numbers be 4x and 5x.

As per given condition we have,

(5x)³-(4x)³=61

125x³-64x³=61

61x³=61

x³=61/61

x³=1

x=1

Now,

4x=4×1=4

5x=5×1=5

Hence required numbers are 4 and 5.

Answer 2

Let the two numbers be 4x and 5x
Then,
(5x^3) - (4x^3)= 61
125x^3- 64x^3=61
61x^3=61
x^3 = 61/61
x^3 = 1
So , x=1
Since , x is equal to 1 The numbers are:
4 and 5..

Hope this helps.
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