Question

two no. when multiplied the result is 8 and when the two no. are added the result is 11
Find the two no.​ ....pls guys answer it tomorrow my test is there....
answer it and get 100 points pls guys pls....​

Answer 1

Answer:

Step-by-step explanation:

Let the two numbers be a and b respectively.

According to the 1st Condition:-

a×b=8

b=$\frac{8}{a}$---------(1)

According to the 2nd Condition:-

a+b=11---------(2)

Putting 'b' from eqⁿ.(1) in eqⁿ.(2) :-

$a+\frac{8}{a}=11$

Taking LCM and then transferring a to the Multiplication with 11:-

$a^{2}+8=11a$

$a^{2}-11a+8=0$

The Quadratic is solved in the attachment.

Hope it will Definitely helps you...

In the attachment it is 'a' in the place of 'x'.

Answer 2

Answer:

I don't no the answer I am sorry