Question

Two non-conducting infinite wires have shapes as shown in the figure. The linear charge densities are as shown. Find the unit vector along the direction of the velocity if the electron just after its release.​

Answer 1

Answer:

Direction of the acceleration of the electron at origin is given as

$a = sin0\hat i + cos0 \hat j$

Explanation:

As we know that the direction of electric field due to charged wire at the position of origin is radially away

So we have

$E = \frac{2k\lambda}{r}$

now the electric field due to wire 1 in the direction 45 degree down the x axis

similarly due to wire 2 the direction of electric field is 45 degree down with - x axis

So we will have net electric field is due to vector sum of the above two wires field

so we will have

$E_{net} = sin 0 \hat i - cos 0 \hat j$

now the direction of acceleration of electron placed on origin is opposite to electric field

SO it will be

$a = sin0\hat i + cos0 \hat j$

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Topic : Electric field

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