Two non-interacting inductors L1 = 2 mH and L2 = 5 mH are connected in parallel then respective ratio of
Answers
Flux is 1 : 1 if Two non-interacting inductors L1 = 2 mH and L2 = 5 mH are connected in parallel
Explanation:
Two inductors are in parallel.
=> potential difference across them is same,
=> V₁=V₂
=> L₁di₁/dt)=L₂(di₂/dt)
=> L₁di₁ =L₂ di₂
integrating
=> L₁i₁ = L₂i₂
=> 2i₁ = 5i₂
=> i₁ / i₂ = 5 / 2
Energy = (1/2) L₁i₁² = (1/2) * 2 i₁ ²
Energy = (1/2)L₂i₂² = (1/2) * 5 i₂ ²
(1/2) L₁i₁² / (1/2)L₂i₂² = (2/5) ( i₁ / i₂)²
=> (1/2) L₁i₁² / (1/2)L₂i₂² = (2/5) (5 / 2)²
=> (1/2) L₁i₁² / (1/2)L₂i₂² = 5 / 2
Flux = LI /N
Flux₁ = L₁i₁/N = 2i₁/N
Flux₂ = L₂i₂/N = 5i₂/N
Flux₁ / Flux₂ = (2i₁/N)/5i₂/N
=> Flux₁ / Flux₂ = (2/5) ( i₁ / i₂)
=> Flux₁ / Flux₂ = (2/5) (5/2)
=> Flux₁ / Flux₂ = 1
=> Flux is 1 : 1
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