Question

two non reactive gas A And B are present in a container with partial pressure 200 and180 mm of Hg . when a third non.reacting gas C added then total pressures became 1atm then mole fraction of c will be

Answer 1

Answer:- Mole fraction of C is 0.5.

Solution:- According to Dalton's law of partial pressures,"Total pressure is the sum of partial pressures of the gases present in the container."

Total pressure = partial pressure of A + partial pressure B + partial pressure of C

partial pressure of C = total pressure -(partial pressure of A + partial pressure of B)

note: (1 atm = 760 mmHg)

Let's plug in the values:

partial pressure of C = 760 mmHg -(200 mmHg + 180 mmHg)

partial pressure of C = 760 mmHg - 380 mmHg = 380 mmHg

Also, partial pressure = total pressure(mole fraction)

So, partial pressure of C = total pressure(mole fraction of C)

mole fraction of C = $\frac{380}{760}$

mole fraction of C = 0.5

So, the mole fraction of C is 0.5.

Answer 2

hope it helps .........