Question

two normal parents have an albino child . what is the probability that their next child will also be an albino?




descibe in the form of punett square

Answer 1

TL;DR: There’s a one-in-four chance for all of the kids.

The most common form of albinism, which affects both the skin and the eyes, requires that both parents carry the particular mutation. There is a one-in-four chance that the first child will have albinism, a two-in-four chance that he or she will be a carrier too (with no symptoms or ill effects), and a one-in-four chance that he or she will be mutation free.

The odds for the second and third child are … exactly the same, regardless of whether the older brother or sister is pigmented or has albinism. (Anticlimactic, right?)

Some background: Both of my daughters have albinism. So, basically, it’s as if someone presented a bag to my husband and me—a bag containing two green marbles and two red ones—and told us, “You have to close your eyes and pick two marbles. If you pick two red ones, your child will have albinism. If you pick any other combination of colors, she won’t.” And we picked the two red ones. Then, when we had our second child, we picked the two red ones again, even though it was unlikely to happen.

Answer 2

Answer: albinism is an autosomal recessive trait. Hence by punnet square we get a probability of 25% offspring to be albino

Explanation: