Two nos. Are in a ratio 3:4 and their sum is 84
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2
let the two nos are 3x and 4x
their sum 3x+4x=7x
so 7x =84
or x=12
so the nos are (3*12) and (4*12)=36 and 48
their sum 3x+4x=7x
so 7x =84
or x=12
so the nos are (3*12) and (4*12)=36 and 48
Answered by
0
let the num be 3x and 4x respectively
a/q
3x+4x=84
x=84/7=12
one number =3x= 36
other num =4x=48.
a/q
3x+4x=84
x=84/7=12
one number =3x= 36
other num =4x=48.
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