Question

Two nos. Are in ratio 2:3,if their lcm is 48.What is the sum of the number?

Answer 1

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Given, two numbers are in the ratio 2 : 3

Let the constant be x

So, let the numbers in the ratio be 2x and 3x

Given, their LCM is 48

LCM of 2x and 3x is 6x because LCM of 2 and 3 is 6 so LCM of 2x and 3x is 6x


According to the question,

6x = 48

➾ x = $\dfrac{48}{6}$

➾ x = 8



Sum of the numbers ➾ 2x + 3x

➾ 5x

➾ 5 × 8

➾ $\boxed {40}$




∴ Sum of the numbers is 40


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Answer 2

$\huge{Answer:}$

$Given:$

Two numbers are in the ratio $2 : 3$

Their $L. C. M. = 48$

Now,

Let the numbers be $2x$ and $3x$

The L. C. M. of $2x$ and $3x$ is $6x.$

[∵ L. C. M. $(2, 3) = 6$ ]

Now,

According to the question,

$6x = 48$

$x = \frac{48}{6}$

$x = 8$

Substituting the value of x:

We get,

$2x = 2(8) = 16$

And,

$3x = 3(8) = 24$

Now,

Adding $16 + 24$

We get,

$16 + 24 = 40$

Therefore,

The sum of the two numbers is $40.$

$\huge{Be\:Brainly!}$