Question

two nos are in the ratio 5:6 . if 8 is subtract from each of the no the ratio become 4:5 find the no

Answer 1

Let,

Ratio be 5x:6x

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According to the question,

$\frac{5x - 8}{6x - 8} = \frac{4}{5} \\ \\ 5(5x - 8) = 4(6x - 8) \\ \\ 25x - 40 = 24x - 32 \\ \\ 25x - 24x = - 32 + 40 \\ \\ x = 40 - 32 \\ \\ x = 8 \\ \\ \\ fraction \: is \: \frac{5 \times 8}{6 \times 8} = \frac{40}{48}$



I hope this will help you

-by ABHAY

Answer 2

Hi ,

Ratio of two numbers = 5 : 6

Let 5x , 6x are the required numbers.

if 8 is subtracted from each of the numbers

the ratio = 4 : 5

( 5x - 8 )/( 6x - 8 ) = 4/5

5( 5x - 8 ) = 4( 6x - 8 )

25x - 40 = 24x - 32

25x - 24x = 40 - 32

x = 8 ,

Therefore ,

Required two numbers are ,

5x = 5 × 8 = 40 ,

6x = 6 × 8 = 48

I hope this helps you.

: )