Math, asked by Zinx, 30 days ago

two nuber are in the ratio of 8 : 3.if the sum of the number are 143.find the smallest number
a)13 b)104 c)39 d)39

Answers

Answered by harsh7646
1

Answer:

d)39

Step-by-step explanation:

Given two numbers are in the ratio 8:3

so let the number be 8x and 3x

According to the question we can write as 8x+3x=143

Which implies 11x=143

Again by transpoing x=143/11

Therfore x=13

So the number are 8x=8(13)=104 and 3x=3(3)=39

Answered by shriyanshigupta16sep
5

Answer:

hey mate ! here is your answer :-

let ratio be x .

8 x and 3 x

after this here we will add this two ratios ok because in the question here sum of number is written ok so , 8x + 3x = 143 .this is the equation which I have made from this question ok so now we will solve this equation ok .

so , 8x + 3x = 143

11x =143

x = 143 / 11

x = 1 3 ok so now we will solve ratio ok

so , 8x = 8 × 13 = 104

3x = 3 × 13 = 39 ok so , you can see that 39 + 104 = 143 ok so here the same number is coming so , the two numbers are :- 39 and 104 ok if you find my solution helpful please mark me as brainliest ok .

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