Two number 9521 and 11374 when divided by a certain number of three digits,leaves same remainder. The sum of digits of such a three digit number is:
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Let the remainder in each case be x
then (11284 - x) and (7655 - x) are exactly
divisible by that three digit number
Difference =(11284−x)−(7655−x)=3629=(11284−x)−(7655−x)=3629
=19×191=19×191
Three digit no. = 191
Sum of digits = 1 + 9 + 1 = 11
I hope this answer was helpful to you.
SHAKUNTALAM GHOSH.
then (11284 - x) and (7655 - x) are exactly
divisible by that three digit number
Difference =(11284−x)−(7655−x)=3629=(11284−x)−(7655−x)=3629
=19×191=19×191
Three digit no. = 191
Sum of digits = 1 + 9 + 1 = 11
I hope this answer was helpful to you.
SHAKUNTALAM GHOSH.
asherunni:
thats not the answer to the question
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