Question

Two number a and b such that LCM(a,b)=36and HCF (a,b)=6 .Find the values of a*b​

Answer 1

Answer:

The possible values of and b are (1, 36) (4,9) (9,4) and (36,1) .

Step-by-step explanation:

Given : The LCM of a,b is 36, HCF is one.

To find : The possible values of a,b ?

Solution :

The two numbers are a and b.

LCM of a,b is 36.

HCF of a,b is 1.

We know that,

\text{Product of two numbers}=HCF\times LCMProduct of two numbers=HCF×LCM

a\times b=36\times 1a×b=36×1

i.e. ab=36ab=36

The possible values of and b are (1, 36) (4,9) (9,4) and (36,1) .

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