two number are in ratio 5:6 when 2 is added to first and 3 is added to second ,they are in ration 4:5. find the number
Answers
Answered by
11
Hi there !!
Here's your answer.
Let the common factor be x
1st number = 5x
2nd number = 6x
Given,
when 2 is added to first and 3 is added to second ,they are in ration 4:5
so, we have the following equation
![\frac{5x + 2}{6x + 3} = \frac{4}{5} \frac{5x + 2}{6x + 3} = \frac{4}{5}](https://tex.z-dn.net/?f=+%5Cfrac%7B5x+%2B+2%7D%7B6x+%2B+3%7D++%3D++%5Cfrac%7B4%7D%7B5%7D+)
Cross multiplying, we have,
![5(5x + 2) = 4(6x + 3) 5(5x + 2) = 4(6x + 3)](https://tex.z-dn.net/?f=5%285x+%2B+2%29+%3D+4%286x+%2B+3%29)
removing and multiplying the brackets,
we have
![25x + 10 = 24x + 12 25x + 10 = 24x + 12](https://tex.z-dn.net/?f=25x++%2B+10+%3D+24x+%2B+12)
![25x - 24x = 12 - 10 25x - 24x = 12 - 10](https://tex.z-dn.net/?f=25x+-+24x+%3D+12+-+10)
![x = 2 x = 2](https://tex.z-dn.net/?f=x+%3D+2)
So,
1st number = 5x = 5 × 2 = 10
2nd Number = 6x = 6 × 2 = 12
Thus ,
The numbers are 10 and 12
Here's your answer.
Let the common factor be x
1st number = 5x
2nd number = 6x
Given,
when 2 is added to first and 3 is added to second ,they are in ration 4:5
so, we have the following equation
Cross multiplying, we have,
removing and multiplying the brackets,
we have
So,
1st number = 5x = 5 × 2 = 10
2nd Number = 6x = 6 × 2 = 12
Thus ,
The numbers are 10 and 12
Answered by
3
let the first number be 5x
another number be 6x
A.T.Q.
5x+2/6x+3=4/5
By cross multiplication;
5 (5x+2)=4 (6x+3)
25x+10=24x+12
transposing 24
25x-24x=12-10
x=2
first number=5x=5×2=10
second number=6x= 6×2=12
another number be 6x
A.T.Q.
5x+2/6x+3=4/5
By cross multiplication;
5 (5x+2)=4 (6x+3)
25x+10=24x+12
transposing 24
25x-24x=12-10
x=2
first number=5x=5×2=10
second number=6x= 6×2=12
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