Question

TWO NUMBER ARE IN RATIO 5:9 ON SUBTRACTING 3 FROM EACH THE RATIO BECOME 1:2. FIND THE NUMBER??​

Answer 1

Step-by-step explanation:

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Answer 2

$\bf \underline{ \underline{\maltese\:Given} }$

$\sf Two \: numbers \: are \: in \: ratio \: 5:9$

$\sf On \: subtracting \: three \: from \: each \: the \: ratio \: becomes \: 1: 2$

$\bf \underline{ \underline{\maltese\: To \: find } }$

$\sf \implies The \: numbers = \: ?$

$\bf \underline{ \underline{\maltese\: Solution } }$

$\sf Let \: us \: assume \: that,$

$\sf \implies First \: number \: be \: 5x$

$\sf \implies Second \: number \: be \: 9x$

$\bf \underline{Now},$

$\sf According \: to \: questions,$

$\sf Equation = \bf \red{ \dfrac{(5x - 3)}{(9x - 3)} = \dfrac{1}{2} }$

$\sf Doing \: cross \: multiplication,$

$\sf \implies 2(5x - 3) = 1(9x - 3)$

$\sf \implies 10x - 6 = 9x - 3$

$\sf \implies 10x - 6 - 9x = 3$

$\sf \implies x - 6 = 3$

$\sf \implies x = - 3 + 6$

$\sf \implies x = 3$

$\sf \underline{ \bigstar \: The \: value \: of \: x \: is \: 3 }$

$\bf \underline{ Therefore},$

$\sf \implies First \: number \: (5x) = \bf 5 \times 3 = 15$

$\sf \implies Second \: number \: ( 9x) = \bf 9\times5=45$