Question

two number are in the ratio 10 : 11 . their sum is 168. find the numbers​

Answer 1

Answer:

The numbers are 80 and 88

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Answer 2

Step-by-step explanation:

$\sf \purple{ \clubs \:Given : }$

• Two numbers are in the ratio 10:11 .
• Their sum is 168 .

$\sf \purple{ \clubs \:To \: find : }$

• The numbers.

$\sf \purple{ \clubs \:Solution : }$

Let numbers be x .

$\sf \: According \: to \: question \\ \sf \: 10x + 11x = 168 \\ \sf \: 21x = 168 \\ \sf \: x = \frac{168}{21} \\ \purple{ \underline{ \boxed{\sf \: x = 8}}}$

• First number $\sf \: = 10x = 10 \times 8 = 80$
• Second number$\sf= 11x = 11 \times 8 = 88$

Which is the required answer .