Question

two number are in the ratio 2:3.if sum of their square is 468 then find the number​

Answer 1

Step-by-step explanation:

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Answer 2

AnswEr:

GivEn:

• Ratio of Numbers - ( 2:3 )
• Sum of their squares = 468

To Find:

• What is the numbers?

SolutiOn:

Let the 1st number be 2x.

again,

Other number be 3x.

Sum of their squares is 468.

The Equation be like,

(2x)² + (3x)² = 468

$\\ \colon\implies\sf{ 4x^2 + 9x^2 = 468 } \\ \\ \implies\sf{ 13x^2 = 468} \\ \\ \implies\sf{ x^2 = \dfrac{ \cancel{468}^{36}}{ \cancel{13}} } \\ \\ \implies\sf{ x^2 = 36} \\ \\ \implies\sf{ x = \sqrt{36} } \\ \\ \implies\sf{ x = \sqrt{6 \times 6}}$

So, After removing number from the Square root the number comes 1 time if it presents 2 times under root;

$\colon\implies\sf{ x = 6}$

Hence,

One Number = 2x

$\implies\sf{ 2 \times 6 = 12}$

Other number = 3x

$\implies\sf{ 3 \times 6 = 18}$