Question

Two number are in the ratio 5:7 on adding 1 to the firstand 3 to
the second their ratio becomes 6/9. Find the numbers.​

Answer 1

Answer:

Step-by-step explanation:

ANSWER:-

Given:-

• Two number are in the ratio 5:7
• Let the ratio constant be x.
• adding 1 to the first and 3 to
• the second their ratio becomes 6/9

Framing the Equation;-

$\dfrac{5x+1}{7x+3} = \dfrac{6}{9}$

Tip:-

• Go sequentially to frame the equation.

$9(5x+1) = 6(7x+3)$

(On cross Multiplication)

$45x+9 = 42x+18$

$45x-42x = 18-9$

$3x = 9$

$x = \dfrac{9}{3}$

$x = 3$

Now, with the required Constants

5x = 5(3) = 15

7x = 7(3) = 21

So, 15 and 21 is the required answer.

Answer 2

Given:

• Ratio of two no. = 5:7
• If we add 1 to the f1st no. and 3 to the 2nd no. then fraction will be 6/9

Find:

• What will be the numbers

Solution:

Let, the f1st number as 5x

and 2nd number as 7x

$\bf{According \: To \: Question}$

➥ $\sf \dfrac{5x + 1}{7x + 3} = \dfrac{6}{9}$

Do, crosss multi-plication

➥ $\sf 9(5x + 1) = 6(7x + 3)$

➥ $\sf 45x + 9 = 42x + 18$

➥ $\sf 45x - 42x = 18 - 9$

➥ $\sf 3x = 9$

➥ $\sf x = \cancel{\dfrac{9}{3}} = 3$

➥ $\sf x = 3$

______________________

F1st number = 5x = 5 × 3 = 15

2nd number = 7x = 7 × 3 = 21