Two number are in the ratio of 3:5 and if 10 be subtracted from each of them , the remainders are in the ratio of 1:5, find the numbers
Answers
Answer:
Let the rational between the two numvers be x
The ratio of two numbers is 3:4.
Thus the two numbers are 3x and 4x
If 5 is subtracted from each of the numbers the ratio becomes 5:7
After substraction of 5, the numbers will be 3x - 5 and 4x - 5. Their ratio
3x - 5 / 4x - 5 = 5 / 7
Solving the equation by cross multiplication
7 (3x - 5) = 5 (4x - 5)
21x - 35 = 20x - 25
21x - 20x = 35 - 25
x = 10
The rational is 10, hence the numbers are
Obe number 3x = 3 × 10 = 30
Second number 4x = 4 × 10 = 40
Thus, the two numbers are 30 and 40
Answer the two numbers are 30 and 40
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Let the two numbers be 3x and 4x.
Subtract 5 from each of these numbers. We get 3x-5 and 4x-5. From the given problem, the ratio of these new numbers is 5:7. Then,
3x−54x−5=57
Cross-mutiplying,
(3x−5)×7=(4x−5)×5
Multiplying 7 inside 3x-5 and 5 inside 4x-5,
21x−35=20x−25
⟹21x−20x=−25+35
⟹x=10
The required numbers are
3x = 3×10 = 30 and
4x = 4×10 = 40.
You tell us about the ratio of two numbers. Then you ask how to find the number.
Should you not be asking how to find the numbers?
3k4k=34
3k−54k−5=57
7(3k−5)=5(4k−5)
21k−35=20k−25
k=10
Original numbers are 30 and 40
Check:
3040=3×104×10=34✓
30–540–5=2535=5×57×5=57✓
ok
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When 1 is added to each of the given two numbers, their ratio becomes 3:4 and when 5 is subtracted from each, the ratio becomes 7:10. What are the numbers?
If two numbers are in the ratio of 5:7 and if 5 is added to each of them, then their ratio becomes 3:4. What is the number?
The ratio of two number are 3:4. If 5 is subtracted from each the ratio becomes 5:7. Find the number?
3 × 4 × 5 × 7 = 420
3 : 4 = 180 : 240
= 30 : 40
5 : 7 = 175 : 245
= 25 : 35
Therefore
30 - 5 = 25
40 - 5 = 35
The trick is multiply the values you have, and Bob's your uncle.
Let n be the common factor between the two numbers. Then:
3n-5/4n-5=5/7
Cross-multiply:
21n-35=20n-25
n=10
3n=30
4n=40
The numbers are 30 and 40 ………
Let the ratio constant be x
Then nos. Are 3x and 4x
Now,5 is subtracted. New nos. Are
3x-5 and 4x-5,
Given
(3x+5):(4x-5)::5:7
Hence, by
Product of means =product of extremes
5(4x-5)=7(3x-5)
Which will give x=10
Hence,
The nos are
30,40
Hope it helps
Given, x/y=3/4————->1
x-5/y-5=5/7—————→2
From eq1, y=4x/3 by substituting the value of y in eq2,
==>7x-35=5(4x-15)/3
==>21x-20x=105–75
Therefore x=30 y=40
Answer:
The numbers are 12 and 20
Hope it will help
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