Question

two number are in the ratio of 5 ratio 6 if 7 is subtract from each of number the ratio becomes 4 ratio 5 find the number​

Answer 1

✬ First Number = 35 ✬

✬ Second Number = 42 ✬

Step-by-step explanation:

Given:

• Two numbers are in ratio of 5 : 6.
• After subtracting 7 from each of number the ratio becomes 4 : 5.

To Find:

• What are the numbers ?

Solution: Let x be the common in given ratio. Therefore

➼ First number = 5x

➼ Second number = 6x

[ Now subtracting seven from both ]

➼ First number = (5x – 7)

➼ Second number = (6x – 7)

A/q

• After subtracting 7 from each of number the ratio becomes 4 : 5.

$\implies{\rm }$ (5x – 7) : (6x – 7) = 4 : 5

$\implies{\rm }$ (5x – 7) / (6x – 7) = 4/5

$\implies{\rm }$ 5(5x – 7) = 4(6x – 7)

$\implies{\rm }$ 25x – 35 = 24x – 28

$\implies{\rm }$ 25x – 24x = – 28 + 35

$\implies{\rm }$ x = 7

So, The two numbers are

➯ First number = 5(7) = 35

➯ Second number = 6(7) = 42

Answer 2

Solution :

Given :

That two numbers are in the ratio 0f 5 : 6 and if 7 is subtracted then the ratio becomes 4 : 5

To find :

The actuall numbers of the ratio

Answer :

Let the number common in the ratio be x

And first and second numbers be 5x and 6x

The two numbers of ratio = 5 : 6

The ratio value when 7 is subtracted = 5x - 7 and 6x - 7

The value of ratio becomes = 4 : 5

So, 5x - 7 : 6x - 7 = 4 : 5

5x - 7 / 6x - 7 = 4 : 5

Let's do cross multiplication

5 ( 5x - 7 ) = 4 ( 6x - 7 )

25x - 35 = 24x - 28

25x - 24x = -28 + 35

x = 7

First number = 5 ( 7 ) = 35

Second number = 6 ( 7 ) = 42

$so \: when \: these \: types \: of \: ratio \: are \: given \: then \: make \: them \: equal \: to \: another \: ratio$