two number are in the ratio of 7:4 and their sum is 630 find the original number
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Question:
- Two numbers are in the ratio of 7 : 4 and their sum is 630. Find the original numbers.
Given:
- The two numbers are in the ratio 7 : 4 with their sum as 630.
To find:
- The original numbers.
Solution:
Let the numbers be 7x and 4x respectively.
Now their ratio = 7 : 4
Their sum = 630
A/q 7x + 4x = 630
11x = 630
x = 630/11
x = 57.27 (approximately)
So the numbers are :
7x = 7 × 57.27
= 400.90 (approx.)
4x = 4 × 57.27
= 229.09 (approx.)
Answer:
- Therefore, the numbers are 400.90 and 229.09 approximately.
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