Two number are respectively 20% and 50% more than a third. what is the first of the second.?
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Let third number is X.
Then first no = 20% of X = 20X/100
Second number = 50% of X = 50X/100
Percent of first no of second no,
= [(20X/100)/(50X/100)] * 100 = (2*100)/20 = 40%
Then first no = 20% of X = 20X/100
Second number = 50% of X = 50X/100
Percent of first no of second no,
= [(20X/100)/(50X/100)] * 100 = (2*100)/20 = 40%
1996shivdalvi:
sorry, but the answer is 80% but i don't know solution please find again
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HeÿA ❄❄
Let third number is X.
Then first no = 20% of X = 20X/100
Second number = 50% of X = 50X/100
Percent of first no of second no,
= [(20X/100)/(50X/100)] * 100 = (2*100)/20 = 40%.
HöPe ïT hèLps u ❤❤
Let third number is X.
Then first no = 20% of X = 20X/100
Second number = 50% of X = 50X/100
Percent of first no of second no,
= [(20X/100)/(50X/100)] * 100 = (2*100)/20 = 40%.
HöPe ïT hèLps u ❤❤
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