two number are such that the first number is 5 times the second number if 10 is added to both the number the first number become 3 times the second number find the two number
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Let's assume the second number as x
So, the first number as 5x
If 10 is added to Both the numbers
First Number = (5x + 10)
Second Number = (x + 10)
According to Question,
First Number = 3 × Second Number
(5x + 10) = 3(x + 10)
=> 5x + 10 = 3x + 30
=> 5x - 3x = 30 - 10
=> 2x = 20
=> x = 20 / 2
=> x = 10
Required Numbers -
First Number = 5x = 5(10) = 50
Second Number = x = 10
Hence, the required numbers are 50 and 10
So, the first number as 5x
If 10 is added to Both the numbers
First Number = (5x + 10)
Second Number = (x + 10)
According to Question,
First Number = 3 × Second Number
(5x + 10) = 3(x + 10)
=> 5x + 10 = 3x + 30
=> 5x - 3x = 30 - 10
=> 2x = 20
=> x = 20 / 2
=> x = 10
Required Numbers -
First Number = 5x = 5(10) = 50
Second Number = x = 10
Hence, the required numbers are 50 and 10
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