two number differ by 3 the sum of twice the number and thrice the greater number is 19 find the number
Answers
Answered by
2
Answer:
5,2
Step-by-step explanation:
let X be the greater number and Y be the less number.
given X-Y=3.
⇒ 2X-2Y=6.------------(a)
and also 3X+2Y=19-----------------(b)
add a and b.
⇒ 5X=25.
x=25/5
X=5
substituting X in (a) we get Y=2.
Prathamkshirsagar:
please solve y=2
substituting X=5 in above equation
5-Y=3
5-3=y
Answered by
3
Heya..,
Your answer is here..,
Two numbers differ by three therefore the equation will be : x - y = 3...(1)×2
The sum of twice the number and thrice greater number is 19 therefore equation will be: 3x + 2y = 19...(2)
2x - 2y = 6
+
3x + 2y = 19
5x. = 25
x = 25/5
x = 5
put x = 5 in equation...(2)
3x + 2y = 19
3×5 + 2y = 19
15 + 2y = 19
2y = 19 - 15
2y = 4
y = 4/2
y = 2
therefore the number is x =5 and y = 2
hope its will helpful to you...
Your answer is here..,
Two numbers differ by three therefore the equation will be : x - y = 3...(1)×2
The sum of twice the number and thrice greater number is 19 therefore equation will be: 3x + 2y = 19...(2)
2x - 2y = 6
+
3x + 2y = 19
5x. = 25
x = 25/5
x = 5
put x = 5 in equation...(2)
3x + 2y = 19
3×5 + 2y = 19
15 + 2y = 19
2y = 19 - 15
2y = 4
y = 4/2
y = 2
therefore the number is x =5 and y = 2
hope its will helpful to you...
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