Question

Two number differ by 3. The sum of twice the smaller number and thrice the greater number is 19. Find the number.

Answer 1

let the two numbers be x and y such that x> y. so equation 1 is x-y = 3. so x = y + 3. equation 2 will be 2y + 3x = 19. replace the value of x in equation 2.
now we get
2y + 3 (y + 3) = 19
2y + 3y + 9 = 19
5y = 19 - 9
5y = 10
y = 10/5 = 2
so x = 2 + 3 = 5
Ans x = 5 and y = 2

Answer 2

Define x:

Let one of the number be x

The other number is x + 3

Solve x:

2x + 3(x + 3) = 19

2x + 3x + 9 = 19

5x + 9 = 19

5x = 10

x = 2

Find the numbers:

One number = x = 2

The other number = x + 3 = 2 + 3 = 5

Answer: The two numbers are 2 and 5