Question

Two number differ by 3 . The sum of twice the smaller number and thrice the greater number is 19 .Find the numbers.​

Answer 1

Answer:

the numbers are 2 and 5

Step-by-step explanation:

Define x:

Let one of the number be x

The other number is x + 3

Solve x:

2x + 3(x + 3) = 19

2x + 3x + 9 = 19

5x + 9 = 19

5x = 10

x = 2

Find the numbers:

One number = x = 2

The other number = x + 3 = 2 + 3 = 5

Answer: The two numbers are 2 and 5

Answer 2

Answer:

Given :-

• Two number differ by 3 . The sum of twice the smaller number and thrice the greater number is 19.

To find :-

• The numbers

Solution:-

Let the first smaller number be x.

So, larger number be x + 3

¤ According to statement,

$\bf \:2x + 3(x + 3) = 19$

$\bf\implies \:2x + 3x + 9 = 19$

$\bf\implies \:5x = 19 - 9$

$\bf\implies \:5x = 10$

$\bf\implies \:{\cancel\dfrac{10}{5} = x}$

$\bf\implies \:x = 2$

So, numbers are 2 and 5.