Math, asked by shubhi12397, 1 year ago

two number of ways that all the letters of the word SWORD can be arranged in such a way that no letter is in its original position is:

Answers

Answered by himanshi6762
13

SWORD

This is simple question of derangement of 5 objects.

{S,W,O,R,D}

Formula for derangement of n objects is:

S=n! [1−11!+12!−13!+...]

HenceS=5![1−11!+12!−13!+14!−15!]=5!

[12!−13!+14−15!]

=120

[12−16+124−1120]

=60−20+5−1

=44 (ANSWER)

help you!!!


maddy0507: nothing...
maddy0507: u won't understand
himanshi6762: thik h
maddy0507: u should understand my feelings
maddy0507: plz don't do that to me
himanshi6762: if you are not giving me then stop it
himanshi6762: please
maddy0507: ok
maddy0507: not giving
himanshi6762: hmm
Answered by apeksha160
0

Answer:

The letters of the word SWORD can be rearranged to get the word WORDS

Step-by-step explanation:

1.One can see what all words can be made by using the letters S W O R D.

2.Start from WORD, WORDS, SOW, ROD, ROW etc.

3. Here the only word possible is WORDS. Each letter of the otiginal word, SWORD is present and no letter is in its original position.



Similar questions