Question

two number p and q are selected without replacement in that order from the integers 1 to 10 what is the probability that p/q is an integer​

Answer 1

Answer:

Step-by-step explanation:

Here replacement is not allowed so total number of cases is 10*9=90.

And possible outcomes are (2,1)(3,1)(4,1)(4,2)(5,1)(6,1)(6,2)(6,3)(7,1)(8,1)(8,2)(8,4)(9,1)(9,3)(10,1)(10,2)(10,5)

Hence probability is 17/90 = 0.1889.

Answer 2

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Answer is 0.210.21

Here number of all possible pairs is 100.

Number of favorable pairs are(10,1),(9,1),(8,1),...(1,1),(10,2),(8,2),(6,2),(4,2),(2,2),(9,3),(6,3),(3,3),(8,4),(4,4),(5,5).(10,1),(9,1),(8,1),...(1,1),(10,2),(8,2),(6,2),(4,2),(2,2),(9,3),(6,3),(3,3),(8,4),(4,4),(5,5).

Hence the number of favorable pairs is 21.21.

Therefore the required answer is 21100.


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