Question

two number s are more then the third number by 50% and 100% then how much is the second number more then the first number.....

Answer 1

Let the third number be 'x'


first number will be 50% more than third number

= x + 50%(x)

= x + 0.5x

= 1.5x

Second number will be 100% more than third number

= x +100%(x)

= x + x

= 2x

three Numbers are 1.5x , 2x , x

Now we need to find -

How much is the second number more than the first number..

Second number - first number

= 2x - 1.5x

= 0.5x more than the first number

Percentage wise
=(increase/original )×100

=( 0.5x/1.5x)×100

= 33.33% or 1/3 more than the first number