Two number x & y are in GP and their sum 30 and sum of their square 408. Find the numbers.
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Two numbers are 15 ± i√21 whose sum is 30 & sum of square 408
Step-by-step explanation:
There is no sense of two numbers being in AP or GP
so may be data is wrong
Let say two numbers are x & y
x + y = 30
x² + y² = 408
=>x² + (30 - x)² = 408
=> x² + 900 + x² - 60x = 408
=> 2x² - 60x + 492 = 0
=> x² - 30x + 246 = 0
=> x = (30 ± √(900 - 984) )/ 2
=> x = 15 ± √(-21)
Result is complex number
x = 15 + i√21 & 15 - i√21
y = 15 - i√21 & 15 + i√21
So numbers are 15 ± i√21
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