Math, asked by lakshmankumarkotha20, 11 months ago

. Two numbers 11284 and 7655, when divided by a certain number of three digits, leaves the same remainder. The sum of digits of such a three-digit number is​

Answers

Answered by Aɾꜱɦ
8

Answer:

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You Have to find a three-digit Number X such that 11284 / X and 7655 / X Leave the same remainder R. In other words:

(equation 1) mX + R = 11284

(equation 2) nX + R = 7655

Where M and n are Whole number Multiples. We want to Combine the Equations, so we'll Make Equation 2 Negative throuhout. That'll Eliminate the Remainder so we can Focus more on X.

(equation 2.1) -nX - R = -7655

Now we Combine the equations to get:

(equation 3) (m - n)X = 11284 - 7655

(equation 3.1) (m - n)X = 3629

m and N are whole Numbers, and Since mX + R is Greater than nX + R, it Follows that m is larger than n; therefore, m - n is also a whole Number. Let's call it z.

(equation 4) zX = 3629

To Find X, we Have to be Able to find three-digit factors of 3629. start by Finding the Smallest Prime number that will Divide evenly into 3629. 2 won't, 3 Won't, 5 won't, 7 won't, 11 won't, 13 won't, 17 won't, but 19 will. 19 x 191 = 3629. And as it turns out, that makes X a three-digit Number, so it satisfies your Requirements and we can stop Searching.

To check, Divide 11284 and 7655 by 191 to confirm that they Give the same remainder:

11284 / 191 = 59 R15

7655 / 191 = 40 R15

#answerwithquality #bal

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