Question

Two numbers A and B are positive and inversely proportional. IF B increases by 100% than A decreases by?​

Answer 1

A decreases by 50%.as a and b are inversely proportional so a=1/b .

Step-by-step explanation:if b is increased by 100% then the no. Becomes 2b and both are inversely proportional so a will become half of it. So a decreases by 50%

Answer 2

If B increased by 100% then A decreases by 50%

Step-by-step explanation:

Inversely proportional relation :

When a quantity is increase then other quantity decrease then, we say two quantities are inversely proportional.

$x\propto\frac{1}{y}$

According to question

$B\propto\frac{1}{A}$

$B=\frac{K}{A}$

Where K=Proportionality constant

B increases by 100%

Therefore , value of B=B+100% of B'=B+B=2B

$2B=\frac{k}{A'}$

Divide equation I by II

Then, we get

$\frac{B}{2B}=\frac{\frac{k}{A}}{\frac{k}{A'}}$

$\frac{1}{2}=\frac{k}{A}\times \frac{A'}{K}$

$\frac{1}{2}=\frac{A'}{A}$

$A'=\frac{1}{2}A$

$A'=\frac{1}{2}\times 100 A$=50% A

Decrease value=Initial value-Final value

Decrease value =100%-50%=50%

Hence,A decreases by 50%

#Learns more:

https://brainly.in/question/2338843 Answered by veronika