Math, asked by pradhanu133, 6 months ago

Two numbers A and B are respectively 30% and 60% less than the third number. By what per cent A is
greater than B?
45%
85%
35%
75%

Answers

Answered by siddideshmukhe17
11

Answer:

75%

Step-by-step explanation:

let third no be x

A=×-×*30/100

A=70*x/100

similary

B=×-×*60/100

B=40*x/100

Now we can see

A is greater than be by 30*×/100

if 40*×/100=100%

then 30*x/100=75%

Answered by qwmagpies
3

Given:

Two numbers A and B are respectively 30% and 60% less than the third number.

To find:

By what per cent A is greater than B.

Solution:

Let the third number be 100.

A is 30% less than the third number means A=100-30

A=70.

B is 60% less than the third number means B=100-60

B=40.

Thus, the value of A is 70 and B is 40.

Now let A is x% greater than B.

So, we can write-

 \frac{70 - 40}{40}  \times 100 \\  =  \frac{30}{40}  \times 100 \\  =75\%

Thus A is 75% greater than B.

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