Question

Two numbers a and b are such that the sum of 5% of a and 4% of b is two-third of the sum of 6% of a snd 8% of



b.Find the ratio of a:b

Answer 1

Hi there!
Here's the answer :

•°•°•°•°•°•<><><<><>><><>•°•°•°•°•°•°

¶ x% of y = (x/100) × y

SOLUTION:

Given,
(5% of a) + (4% of b) = (2/3)×[(6% of a) + (8% of b)

=> (5a/100) + (4b/100) = (2/3)×[(6a/100) + (8b/100)]

=> (5a/100) + (4b/100) = (4a/100) + (16b/300)

=> (5a/100) - (4a/100) = (16b/300) - (4b/100)

=> a[(5/100) - (4/100)] = b[(16/300) - (4/100)]

=> a(1/100) = b(4/300)

=> a = b(4/3)

=> (a/b) = (4/3)

•°• a : b = 4 : 3

Thus, the required ratio is 4 : 3.


•°•°•°•°•°<><><<><>><><>•°•°•°•°•°

¢#£€®$


:)



Hope it helps

Answer 2

Answer:

a : b = 4 : 3

Step-by-step explanation :

According to the given condition is the question :

Two numbers a and b are such that the sum of 5% of a and 4% of b is two-third of the sum of 6% of a and 8% of b

⇒ (5% of a) + (4% of b) = (2/3) × [(6% of a) + (8% of b)

⇒ 0.05a + 0.04b = 2/3 × (0.06a + 0.08b)

⇒ 0.15a + 0.12b = 0.12a + 0.16b

⇒ 0.03a = 0.04b

⇒ a/b = 4/3

⇒ a : b = 4 : 3