Two numbers A and B are such that the sum of 9% of A and 5% of B is two-third of the sum of 3% of A and 8% of B.Find the ratio A:B.
Answers
Answer:
SOLUTION:
Given,
(5% of a) + (4% of b) = (2/3)×[(6% of a) + (8% of b)
=> (5a/100) + (4b/100) = (2/3)×[(6a/100) + (8b/100)]
=> (5a/100) + (4b/100) = (4a/100) + (16b/300)
=> (5a/100) - (4a/100) = (16b/300) - (4b/100)
=> a[(5/100) - (4/100)] = b[(16/300) - (4/100)]
=> a(1/100) = b(4/300)
=> a = b(4/3)
=> (a/b) = (4/3)
•°• a : b = 4 : 3
Thus, the required ratio is 4 : 3.
Step-by-step explanation:
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Answer:
The ratio of A to B is 11:7.
Step-by-step explanation:
Suppose two numbers A and B are related x:y.
So we can write A in the form (xk) and B in the form (yk), where k is a constant.
Now, after the problem statement,
9% AL + 5% SI = 2/3 (3% AL + 8% SI)
Substituting the values of A and B, we get:
9/100(xk) + 5/100(yk) = 2/3(3/100(xk) + 8/100(yk))
By simplifying the previous equation, we get:
9xk/100 + 5yk/100 = 2/3(3xk/100 + 8yk/100)
9xk/100 + 5yk/100 = 2xk/100 + 16yk/100
7xk/100 = 11yk/100
x/a = 11/7
So, the ratio of A to B is 11:7.
So, the solution to the given problem is a ratio of A to B of 11:7.
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