Math, asked by tarini44, 1 year ago

Two numbers a and b are such that the sum of5% of a and 4% of b is the two third of the sum of 6% of a and 8% of b . Find the ratio a:b


plzz answer <br /><br />


salute to whoever does​

Answers

Answered by gujjarankit
1

ratio a:b =4:3

hope it will be helpful

Attachments:

tarini44: sooooo much
tarini44: it's actually 3:4
gujjarankit: srry i don't think so
gujjarankit: as a:b is asked
tarini44: 3a:4b
tarini44: then a:b should be 3:4
gujjarankit: maybe it is ....but from my point of view it is 3a=4b thereafter a/b = 4/3 thus a:b =4:3 ...apologies if i m wrong
tarini44: no no u r right ......scholar
gujjarankit: thanxx a lot
tarini44: welcome
Answered by jaskirat13
1

SOLUTION:

Given,

(5% of a) + (4% of b) = (2/3)×[(6% of a) + (8% of b)

=> (5a/100) + (4b/100) = (2/3)×[(6a/100) + (8b/100)]

=> (5a/100) + (4b/100) = (4a/100) + (16b/300)

=> (5a/100) - (4a/100) = (16b/300) - (4b/100)

=> a[(5/100) - (4/100)] = b[(16/300) - (4/100)]

=> a(1/100) = b(4/300)

=> a = b(4/3)

=> (a/b) = (4/3)

•°• a : b = 4 : 3

Thus, the required ratio is 4 : 3.

HOPE IT WILL HELP...

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