Question

two numbers A and B
L.C.M+H.C.F=592
L.C.M-H.C.F=518
A+B=296
then what is the values of A andB

Answer 1

2LCM =1110
lcm=555(by solving above equation)
2hcf=74
hcf=37
A.B=lcm×hcf
=555×37
=20535
A+B=296 from this B=(296-A)
then,
A×(296-A)=20535
by solving the above quatratic equation
A^2-296A+20535=0
we get two values 111 and185
if A=185 thenB=111
if A=111then A=185