Two numbers add to 87. If one number is doubled
and the other is halved the new sum is 111.
What was the larger of the original numbers?
The larger of the original numbers =
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Answer:
Let one number be x.
So, other number = 87-x.
The doubled number = 2x.
The halved number = (87-x)/2
According to condition,
2x + (87-x)/2 = 111
Or, {4x + (87-x)}/2 = 111
Or, {4x + (87-x)} = 111 × 2
Or, 3x + 87 = 222
Or, 3x = 222 - 87
Or, 3x = 135
Or, x = 135/3
Or, x = 45
So, x = 45
87 - x = 87 - 45 = 42
Hence, larger of the original numbers is 45.
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