'Two numbers add up to 70. One third of the larger number is 10 more than one seventh of the smaller number. Find the numbers.' - Please explain the sum clearly.
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Let the larger number be 'x' and the smaller number be 'y'.
Given : x + y = 70
1/3* x = 10 + 1/7* y. ~(1)
x + y = 70
x = 70 - y ~(2)
substitute (2) in (1)
1/3 * ( 70 - y ) = 10 + 1/7 *y
70/3 - y/3 = 10 + y/7
y/7 + y/3 = 70/3 - 10
3y + 7y / 21 = 70 - 30 / 3
10y/ 21 = 40/3
10y = 40/3 * 21
10y = 40 * 7
10y = 280
y = 280 /10
y = 28
x = 70 - y
x = 70 - 28
x = 42
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