Question

Two numbers are 20% and 45% less than a third number. by how much percent is the second number less than the first number

Answer 1

Let,
1st number = x
2nd number = y
3rd number = z

According to question
x = z - 20% ——-(1)
y = z - 45% ———(2)

Subtract 2nd equation from 1st equation

x - y = z - 20% - z + 45%
x - y = 25%
y = x - 25% ———-(3)

3rd equation says that 2nd number is 25% less than 1st number.

Answer 2

Answer:

31 1/4%

Step-by-step explanation:

Let the third number be 100

The first number is 80 and second number is 55.

% the second number is less than the first

= (80-55) / 80 x 100

= 25/80 x 100

= 125/4

= 31 1/4%

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