Question

Two numbers are 30% and 60% more than a third number respectively. Find the ratio of the first two numbers.​

Answer 1

Given,

Two numbers are 30% and 60% more than a third number.

To find,

The ratio of the first two numbers.

Solution,

We can simply solve this mathematical problem using the following process:

Let us assume that the third number is x.

Mathematically,

P% of a number A is calculated as follows;

(P/100)×A

{Statement-1}

Now, according to the question;

The first number is 30% more than the third number

=> The first number = (third number) + (30% of the third number)

= x + (30% of x)

= x + (30/100)×x

{according to statement-1}

= x + 3x/10

= 13x/10

And, the second number is 60% more than the third number

=> The second number = (third number) + (60% of the third number)

= x + (60% of x)

= x + (60/100)×x

{according to statement-1}

= x + 6x/10

= 16x/10

Now, the ratio of the first two numbers

= (first number)/(second number)

= (13x/10)/(16x/10)

= 13/16

= 13:16

Hence, the ratio of the first two numbers is equal to 13:16.