Two numbers are differ by 3 . the sum of twice is the smaller number the greater number is 19. find the numbers
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let the smallest number be x and the largest be y
according to first equation
x-y=3
x=3+y
according to second equation
2x+y=19
2(3+y)+y=19
6+2y+y=19
3y=13
y=13/3
x=3+y
x=3+(13/3)
x=9+13/3
x=22/3
according to first equation
x-y=3
x=3+y
according to second equation
2x+y=19
2(3+y)+y=19
6+2y+y=19
3y=13
y=13/3
x=3+y
x=3+(13/3)
x=9+13/3
x=22/3
swtyamsingh:
thats what the problem is
pls try it
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