two numbers are differ by 4 and their product is 192. find the numbers.
Answers
Answered by
5
let the no be x
x(x+4)=192
x^2+4x=192
x^2+4x-192=0
x^2+16x-12x-192=0
x(x-16)-12(x-16)=0
(x-12)(x-16)=0
hence x-12=0=12 or x-16=0 x=16
x(x+4)=192
x^2+4x=192
x^2+4x-192=0
x^2+16x-12x-192=0
x(x-16)-12(x-16)=0
(x-12)(x-16)=0
hence x-12=0=12 or x-16=0 x=16
Similar questions