Question

Two numbers are in a ratio 4:3 their sum is 70 find there numbers

Answer 1

The two numbers are 40 and 30

Given :

Two numbers are in the ratio 4 : 3 and their sum is 70

To find :

The two numbers

Solution :

Step 1 of 2 :

Form the equation

Here it is given that the two numbers are in the ratio 4 : 3

Let the numbers are 4x and 3x

Now their sum is 70

By the given condition

4x + 3x = 70

Step 2 of 2 :

Find the numbers

$\displaystyle \sf{ 4x + 3x = 70 }$

$\displaystyle \sf{ \implies 7x = 70}$

$\displaystyle \sf{ \implies x = \frac{70}{7} }$

$\displaystyle \sf{ \implies x = 10}$

First number = 4x = 4 × 10 = 40

Second number = 3x = 3 × 10 = 30

Hence the two numbers are 36 and 48

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Answer 2

Answer:

The first number is $40$ and the second number is $30$.

Step-by-step explanation:

Given:

Two numbers are in the ratio $4 : 3$ and their totality exists at $70$.

To find:

The two numbers.

Step 1

The two digits are in the ratio 4 : 3 and their sum is $70$.

Let the numbers be $4x$ and $3x$.

then sum exists $70$

By the given condition

$4x + 3x = 70$

Step 2

To find the first numbers

First number $= 4x$

$= 4 * 10 = 40$

Second number$= 3x$

$= 3 * 10 = 30$

Hence the two numbers are $30$ and $40$.

Therefore, the first number is $40$ and the second number is $30$.

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