Math, asked by anyaemanrahman, 3 months ago

Two numbers are in ratio 4 : 5. If the sum of the numbers is 90, find the numbers

Answers

Answered by ATRIJIT
6

Answer:

Let the numbers be 4x and 5x

4x + 5x = 90

9x = 90

x = 9

4x = 40

5x = 50

Therefore, the numbers are 40 and 50.

Step-by-step explanation:

THANK YOU

Answered by payalchatterje
0

Answer:

Required two numbers are 40 and 50.

Step-by-step explanation:

Given,two numbers are in ratio 4 : 5.

Let the first number be 4x and second number be 5x.

It is also given,the sum of the numbers is 90.

According to question,

4x + 5x = 90

We are adding 4x and 3x,

9x = 90 \\ x =  \frac{90}{9}

90 is dividing by 9,

x = 10

Therefore first number is

(4 \times 10) = 40 \\ (5 \times 10) = 50

This is a problem of Algebra.

Some important Algebra formulas:

{(x + y)}^{2}  =  {x}^{2}  + 2xy +  {y}^{2} \\  {(x  -  y)}^{2}  =  {x}^{2}   -  2xy +  {y}^{2} \\  {(x  + y)}^{3}  =  {x}^{3}  + 3 {x}^{2} y + 3x {y}^{2}  +  {y}^{3}  \\   {(x   -  y)}^{3}  =  {x}^{3}   -  3 {x}^{2} y + 3x {y}^{2}   -  {y}^{3} \\  {x}^{3}  +  {y}^{3}  =  {(x  +  y)}^{3}  - 3xy(x + y) \\ {x}^{3}   -  {y}^{3}  =  {(x   -   y)}^{3}   +  3xy(x  -  y) \\  {x}^{2}  -  {y}^{2}  = (x + y)(x - y) \\    {x}^{2}  +  {y}^{2}  =  {(x - y)}^{2}   + 2xy \\ {x}^{2}   -  {y}^{2}  =  {(x   + y)}^{2}  - 2xy \\  {x}^{3}  -  {y}^{3}  = (x - y)( {x}^{2}  + xy +  {y}^{2} ) \\ {x}^{3}   +   {y}^{3}  = (x - + y)( {x}^{2}   -  xy +  {y}^{2} )

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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