Question

TWO NUMBERS ARE IN RATIO 5:6. IF 8 IS SUBTRACTED FROM EACH OF THE NUMBERS, THE RATIO BECOMES 4:5 THEN THE NUMBERS ?​

Answer 1

Answer:

40 and 48

Step-by-step explanation:

Assume the number be a.

Two numbers are in the ratio 5:6.

→ 5a : 6a

If 8 is subtracted from each number, the ratio becomes 4:5.

→ (5a - 8)/(6a - 8) = 4/5

→ 5(5a - 8) = 4(6a - 8)

→ 25a - 40 = 24a - 32

→ 25a - 24a = - 32 + 40

→ a = 8

Therefore,

→ 5a = 5(8) = 40

→ 6a = 6(8) = 48

Hence, the numbers are 40 and 48.

Answer 2

Answer:

Numbers are 40 and 48

Step-by-step explanation:

Given :-

TWO NUMBERS ARE IN RATIO 5:6. IF 8 IS SUBTRACTED FROM EACH OF THE NUMBERS, THE RATIO BECOMES 4:5

To Find :-

Numbers

Solution :-

Let,

Numbers = 5x and 6x

When 8 is added

5x + 8/6x + 8 = 4/5

5(5x - 8) = 4(6x - 8)

25x - 40 = 24x - 32

25x - 24x = -32 + 40

x = 8

Numbers are

5x = 5(8) = 40

6x = 6(8) = 48