two numbers are in ratio 6:11 .ON ADDING 2 TO THE FIRST AND 7 TO the second .their ratio become 8:15.find the number
tangiant:
(6x+2)/(11x+7)=8/15
Answers
Answered by
40
let be the number s are x and y
first condition
x:y = 6:11
x/y = 6/11
11x = 6y
x = 6y/11......................,...............(1)
(x+2)/(y+7) = 8:15
15(x+2) = 8(y+7)
15x +30 = 8y + 56
15x - 8y = 56-30
15 x - 8y= 26........,...............(2)
putting the value of x in equation (2) from (1)
15×6y/11 - 8y = 26
90y /11 -8y = 26
multiple by 11 in both sides
90y -88y = 286
2y = 286
y = 143
putting the value of y in equation (1)
x = 6×143/11
x = 78
x=78
y= 143
hope it helpful for you
first condition
x:y = 6:11
x/y = 6/11
11x = 6y
x = 6y/11......................,...............(1)
(x+2)/(y+7) = 8:15
15(x+2) = 8(y+7)
15x +30 = 8y + 56
15x - 8y = 56-30
15 x - 8y= 26........,...............(2)
putting the value of x in equation (2) from (1)
15×6y/11 - 8y = 26
90y /11 -8y = 26
multiple by 11 in both sides
90y -88y = 286
2y = 286
y = 143
putting the value of y in equation (1)
x = 6×143/11
x = 78
x=78
y= 143
hope it helpful for you
Answered by
54
Let the two numbers be 6x and 11x
On adding 2 to the first number = ( 6x + 2 )
On adding 7 to the second number = ( 11x + 7 )
Their ration becomes 8 : 15
Therefore, the numbers becomes 15(6x + 2) and 8(11x + 7)
ATQ,
15(6x + 2) = 8(11x + 7)
90x + 30 = 88x + 56
90x - 88x = 56 - 30
2x = 26
x =
x = 13
1st number = 6x = 6 × x = 6 × 13 = 78
2nd number = 11x = 11 × x = 11 × 13 = 143
On adding 2 to the first number = ( 6x + 2 )
On adding 7 to the second number = ( 11x + 7 )
Their ration becomes 8 : 15
Therefore, the numbers becomes 15(6x + 2) and 8(11x + 7)
ATQ,
15(6x + 2) = 8(11x + 7)
90x + 30 = 88x + 56
90x - 88x = 56 - 30
2x = 26
x =
x = 13
1st number = 6x = 6 × x = 6 × 13 = 78
2nd number = 11x = 11 × x = 11 × 13 = 143
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