Question

Two numbers are in ratio 7: 11. If 7 is added to each of the numbers, the ratio becomes 2: 3. The smaller numberis​

Answer 1

Answer:

Given

′ 2 ′ no's are in the ratio 7:11

′7 ′ is added to these no's then the ratio 2:3

Let 1st no= 7x

2nd no= 11x

7x+7/11x+7 = 2/3

3(7x+7)=2(11x+7)

21x+21=22x+14

22x−21x=21−14

x=7

1st no =7×7=49

2nd no =11×7=77

Answer 2

Answer:

let the numbers are 7x and 11x

so,

(7x+7)/(11x+7)=2/3

=> 2(11x+7)=3(7x+7)

=> 22x+14=21x+21

=> 22x-21x=21-14

=> x=7

so the numbers are 7×7=49 and 7×11=77

so the smaller number is 49