two numbers are in ratio 7:4 if their difference is 72 find the numbers
Answers
Answered by
233
Hey!
Let one number be 4x
Another be 7x
7x-4x = 72
3x = 72
x = 72/3
x = 24
One number 24*7 = 168
Another number 24*4 = 96
Hope this helps.. _/\_
Let one number be 4x
Another be 7x
7x-4x = 72
3x = 72
x = 72/3
x = 24
One number 24*7 = 168
Another number 24*4 = 96
Hope this helps.. _/\_
Answered by
75
Let the common ratio be x.
Let 7x be the first number.
Let 4x be the second number.
Given that the difference of two numbers = 72.
7x - 4x = 72
3x = 72
x = 72/3
x = 24.
So, first number = 7 * 24 = 168.
and second number = 4 * 24 = 96.
Therefore the numbers are 168 and 96.
Verification:
7x - 4x = 72
7(24) - 4(24) = 72
168 - 96 = 72
72 = 72.
Hope this helps!
Let 7x be the first number.
Let 4x be the second number.
Given that the difference of two numbers = 72.
7x - 4x = 72
3x = 72
x = 72/3
x = 24.
So, first number = 7 * 24 = 168.
and second number = 4 * 24 = 96.
Therefore the numbers are 168 and 96.
Verification:
7x - 4x = 72
7(24) - 4(24) = 72
168 - 96 = 72
72 = 72.
Hope this helps!
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