Two numbers are in ratio of 2:5 when 7 is subtracted from each the ratio becomes 1:6 the original numbers are?
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let the numerator be X and the denominator be y
according to the question ,
X/ y =2/5 and. ( eq1)
(x-7)/( y-7)=1/6. ( eq2)
5x=2y( from eq1)
y=5/2x. (eq 3)
6(x-7)=y-7( from eq2 )
6(x-7)=(5x/2)-7. ( from eq 3)
6x-42=(5x/2)-7
-42+7=5x/2-6x
-35=(5x/2)-(12x/2)
-35=(-7x/2)
-35*2=-7x
X=( -35*2)/-7
X=5*2
X= 10
hope you find the answer useful^_^
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