two numbers are in ratio of 4 ratio 7 the difference of the squares is 297 find the numbers
Answers
Answered by
13
Let the numbers be 4a and 7a
According to question
(7a)^2 - (4a)^2 = 297
=> 49a^2 - 16a^2 = 297
=> 33a^2 = 297
=> a^2 = 9
=> a = 3
First number = 12
Second number = 21
According to question
(7a)^2 - (4a)^2 = 297
=> 49a^2 - 16a^2 = 297
=> 33a^2 = 297
=> a^2 = 9
=> a = 3
First number = 12
Second number = 21
Answered by
3
let the no be a= 4x and b=7x
so,
(7x)^2-(4x)^2=297
49x^2-16x^2=297
33x^2=297
x^2=297/33
x=√99
x=9.94
a=4×9.94=39.76
b=7×9.94=69.58
so,
(7x)^2-(4x)^2=297
49x^2-16x^2=297
33x^2=297
x^2=297/33
x=√99
x=9.94
a=4×9.94=39.76
b=7×9.94=69.58
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